2008 USAMO Problems
Contents
Day 1
Problem 1
(Titu Andreescu) Prove that for each positive integer , there are pairwise relatively prime integers
, all strictly greater than 1, such that
is the product of two consecutive integers.
Problem 2
(Zuming Feng) Let be an acute, scalene triangle, and let
,
, and
be the midpoints of
,
, and
, respectively. Let the perpendicular bisectors of
and
intersect ray
in points
and
respectively, and let lines
and
intersect in point
, inside of triangle
. Prove that points
,
,
, and
all lie on one circle.
Problem 3
(Gabriel Carroll) Let be a positive integer. Denote by
the set of points
with integer coordinates such that
A path is a sequence of distinct points
in
such that, for
, the distance between
and
is
(in other words, the points
and
are neighbors in the lattice of points with integer coordinates). Prove that the points in
cannot be partitioned into fewer than
paths (a partition of
into
paths is a set
of
nonempty paths such that each point in
appears in exactly one of the
paths in
).
Day 2
Problem 4
(Gregory Galparin) Let be a convex polygon with
sides,
. Any set of
diagonals of
that do not intersect in the interior of the polygon determine a triangulation of
into
triangles. If
is regular and there is a triangulation of
consisting of only isosceles triangles, find all the possible values of
.
Problem 5
(Kiran Kedlaya) Three nonnegative real numbers ,
,
are written on a blackboard. These numbers have the property that there exist integers
,
,
, not all zero, satisfying
. We are permitted to perform the following operation: find two numbers
,
on the blackboard with
, then erase
and write
in its place. Prove that after a finite number of such operations, we can end up with at least one
on the blackboard.
Problem 6
(Sam Vandervelde) At a certain mathematical conference, every pair of mathematicians are either friends or strangers. At mealtime, every participant eats in one of two large dining rooms. Each mathematician insists upon eating in a room which contains an even number of his or her friends. Prove that the number of ways that the mathematicians may be split between the two rooms is a power of two (i.e., is of the form for some positive integer
).
See Also
2008 USAMO (Problems • Resources) | ||
Preceded by 2007 USAMO |
Followed by 2009 USAMO | |
1 • 2 • 3 • 4 • 5 • 6 | ||
All USAMO Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.