2018 AIME II Problems/Problem 4
Contents
Problem
In equiangular octagon ,
and
. The self-intersecting octagon
encloses six non-overlapping triangular regions. Let
be the area enclosed by
, that is, the total area of the six triangular regions. Then
, where
and
are relatively prime positive integers. Find
.
Solution
We can draw and introduce some points.
The diagram is essentially a 3x3 grid where each of the 9 squares making up the grid have a side length of 1.
In order to find the area of , we need to find 4 times the area of
and 2 times the area of
.
Using similar triangles and
(We look at their heights),
. Therefore, the area of
is
Since
and
,
and
.
Therefore, the area of is
Our final answer is
Solution 2
is essentially a plus sign with side length 1 with a few diagonals, which motivates us to coordinate bash. We let
and
. To find
's self intersections, we take
And plug them in to get where
is the intersection of
and
, and
is the intersection of
and
.
We also track the intersection of and
to get
.
By vertical symmetry, the other 2 points of intersection should have the same x-coordinates. We can then proceed with Solution 1 to calculate the area of the triangle (compare the -coordinates of
and
and
).
See Also
2018 AIME II (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.